On 3 Oct 2014 07:09, "T J" <[email protected]> wrote: > > Any bites on this? > > On Wed, Sep 24, 2014 at 12:23 PM, T J <[email protected]> wrote: >> Python's round function goes away from zero, so I am looking for the NumPy equivalent (and using vectorize() seems undesirable). In this sense, it seems that having a ufunc for this type of rounding could be helpful. >> >> Aside: Is there interest in a more general around() that allows users to specify alternative tie-breaking rules, with the default staying 'round half to nearest even'? [1] >> --- >> [1] http://stackoverflow.com/questions/16000574/tie-breaking-of-round-with-numpy
I like the solution given in that Stack Overflow post, namely using ctypes to call fesetround(). Does that work for you?
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