[Numpy-discussion] Equality of dtypes does not imply equality of type kinds

[Alexander Belopolsky]

Consider this (on a 64-bit platform):

>>> numpy.dtype('q') == numpy.dtype('l')
True

but

>>> numpy.dtype('q').char == numpy.dtype('l').char
False

Is that intended?  Shouldn't dtype constructor "normalize" 'l' to 'q' (or
'i')?

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