> This is not correct. The discrete form of the Heaviside step function has > the value 1 for x == 0. >
Yeah, I was looking at it and wondering if I'd misremembered the definition. Assuming you're implementing the discrete Heaviside function, H[0] = 1 as Sturla notes.
_______________________________________________ NumPy-Discussion mailing list NumPy-Discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion
