Yes. Unless I'm missing something, expanding the variables shows this as a trivial truth:
OUT = (LS.1 OR LS.2 OR LS.3 OR LS.4 OR LS.5) AND LS.4 = LS.4 On Sat, Sep 14, 2013 at 11:53 AM, Stewart Mackenzie <[email protected]>wrote: > Thank you Chetan, for the time and effort to answer my question. I have > one more question for anyone willing, (as C and X weren't identical so I > need to try again!) > > 'htm.SDR' is the function to generate a 2048 bit vector. > > Now I have a list L, consisting of 5 elements, with values: 0:'bee', > 1:'horse', 2:'flower', 3:'cow', 4:'dog'. I now LS = htm.SDR(D). LS now > consists of a list of SDRs corresponding to each consecutive element's > value in L. Ie LS.0 sparse represents L.0, LS.4 sparse represents L.4 etc. > > I now ULS = boolean.OR-5-Way(LS). Then I do a OUT=boolean.AND(ULS,LS.4). > > Is OUT _exactly_ the same as LS.4? > > Kind regards > > Stewart > -- > Sent from my Android device with K-9 Mail. Please excuse my brevity. > > _______________________________________________ > nupic mailing list > [email protected] > http://lists.numenta.org/mailman/listinfo/nupic_lists.numenta.org > >
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