Nutch Crawler wrote:
int n = group.activeCount();
Thread[] list = new Thread[n];
group.enumerate(list);
boolean noMoreFetcherThread = true; // assumption
for (int i=0; i<n; i++) {
// check for unused positions in the array if (list[i] == null) continue;
String name = list[i].getName(); if (name.startsWith(THREAD_GROUP_NAME)) // prove it
You may be right. Could you please test if adding the line above solves this problem?
-- Best regards, Andrzej Bialecki
------------------------------------------------- Software Architect, System Integration Specialist CEN/ISSS EC Workshop, ECIMF project chair EU FP6 E-Commerce Expert/Evaluator ------------------------------------------------- FreeBSD developer (http://www.freebsd.org)
------------------------------------------------------- This SF.Net email is sponsored by: InterSystems CACHE FREE OODBMS DOWNLOAD - A multidimensional database that combines robust object and relational technologies, making it a perfect match for Java, C++,COM, XML, ODBC and JDBC. www.intersystems.com/match8 _______________________________________________ Nutch-developers mailing list [EMAIL PROTECTED] https://lists.sourceforge.net/lists/listinfo/nutch-developers
