I was dealing with a problem earlier on today that required me to
check software versions against each other in the form of '1.2.3.4'
and '1.86.13' etc. and came up with this code to do it:
# bigger? '1.3.1.1', '1.4'
def bigger?(a,b)
a_parts = a.split '.'
b_parts = b.split '.'
(a_parts.size > b_parts.size ? a_parts.size : b_parts.size).times {|
i|
if (a_parts[i].to_i || 0) > (b_parts[i].to_i || 0)
return(true)
end
if (a_parts[i].to_i || 0) < (b_parts[i].to_i || 0)
return (false)
end
}
return false
end
(mirrored here: http://gist.github.com/108740)
The code will return true only if software version a is higher than
software version b. It will return false if the versions are matched
of if version b is higher.
And I figured it might be fun to send it out and see if people could
come up with a shorter/better/more exciting way of doing this. It is
Friday after all, party on ;)
Will.
--
Will Jessop
Super Shiny Robot Limited - Professional web design and development
t: 07939 547 962
w: http://supershinyrobot.com/
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