mmm... in some cases, but not always. In my example if you do
index.php
<?php
include "/path/to/file_a.php";
?>
using $_SERVER['SCRIPT_FILENAME'] in do_something() will return /path/
to/index.php, but I really want /path/to/file_a.php which is the file
calling the function defined in file_b.php... makes sense?
On 2/10/2008, at 9:59 AM, Nathan Kennedy wrote:
Hey Matt,
If I understand your question correctly, I think you'll find that
$_SERVER['SCRIPT_FILENAME'] will contain the value that you are after.
Thanks,
Nathan.
Web Controlled Robotic Arm and Beetle
http://www.kennedytechnology.com
-----Original Message-----
From: [email protected] [mailto:[EMAIL PROTECTED] On
Behalf
Of Matias Gertel
Sent: Thursday, 2 October 2008 9:20 a.m.
To: NZ PHP Users Group
Subject: [phpug] dirname of file with calling function
Hi all,
I've been wondering... I'm a big fan of dirname(__FILE__) but
sometimes I have a situation where I would like to know the path of
the file where my function is called.
I'll explain:
file_a.php is:
<?php
include "/path/to/file_b.php";
do_something();
?>
file_b.php is:
<?php
function do_something() {
// I wonder what's the dirname of file_a.php ?
}
?>
I know this can be done using debug_backtrace but it's not really
ideal. I was wondering if someone had this situation and solved it in
some elegant way.
Cheers,
Matt
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