Surely the obvious solution is: ((($w[1]-2)%3+($w[1]-1)%3)>1)
=P On Jan 16, 4:53 pm, Michael <[email protected]> wrote: > On Fri, 16 Jan 2009 16:47:01 Mike Cochrane wrote: > > > Or slightly easier to read assuming $substr was supposed to just be substr: > > > (in_array($w[1], array(3, 4, 6, 7, 9)) > > > - Mike > > Yes. It was a typo, but even with that fixed my original code did not work as > I had wanted. > > It is now working good with the assistance from yourself and others, > thanks :-) > > Michael --~--~---------~--~----~------------~-------~--~----~ NZ PHP Users Group: http://groups.google.com/group/nzphpug To post, send email to [email protected] To unsubscribe, send email to [email protected] -~----------~----~----~----~------~----~------~--~---
