I believe you will have a very hard time doing this in straight SQL, as
it is not flexible enough. The 'number of matches' part is particularly
difficult. If mysql supports user-defined functions as MSSQL Server
does, you might have a shot at it...
But I would try to use an approach that does more of the logic in PHP.
Use SQL to get a set of employees which have *any* skill in common with
what the company wants, then use PHP to handle the prioritisation. You
may need to do subsequent lookups for each employee to find out how many
skills there are in common, but this may not be a performance issue
depending on how many records you expect there to be.
R
On 17/08/10 09:17, Brendan Brink wrote:
hi there,
have a query with building an SQL query...
SELECT DISTINCT(e.id),cs2.company_id as companyid, count(es2.skill) as
skillswanted FROM employees_personal e INNER JOIN employees_skills es2
on es2.employee_id = e.id INNER JOIN company_skill cs2 on cs2.skill =
es2.skill WHERE cs2.company_id = '117' AND 1 GROUP BY companyid order
by skillswanted DESC, e.first_name,e.last_name
Basically...
Employees_personal have skills in the employees_skills table,
Companies have skills they require in company_skill table
i want to find all employees who have skills that match skills in the
company skill table, and then order by the number of matches desc to
find most suitable employee.
... currently the query is not giving any errors, but it only returns
one employee, when I know there should be alot more results...
also...ideally would like to create a HAVING clause on the number of
skillswanted...so can say only display employees who match at least 2
skills.
thanks..for any help would be appreciated...
--
Phone (04) 381 4827 or 021 823 129
Skype rimu123
Web http://rimu.geek.nz/
--
NZ PHP Users Group: http://groups.google.com/group/nzphpug
To post, send email to [email protected]
To unsubscribe, send email to
[email protected]
