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https://issues.apache.org/jira/browse/OAK-1392?page=com.atlassian.jira.plugin.system.issuetabpanels:all-tabpanel
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Alex Parvulescu resolved OAK-1392.
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       Resolution: Fixed
    Fix Version/s: 0.17

this looks good enough, we can pursue the checksum ideas mentioned here in the 
future if needed.

> SegmentBlob.equals() optimization
> ---------------------------------
>
>                 Key: OAK-1392
>                 URL: https://issues.apache.org/jira/browse/OAK-1392
>             Project: Jackrabbit Oak
>          Issue Type: Improvement
>          Components: core
>            Reporter: Jukka Zitting
>             Fix For: 0.17
>
>         Attachments: 0001-OAK-1392-SegmentBlob.equals-optimization.patch, 
> OAK-1392-v0.patch
>
>
> The current {{SegmentBlob.equals()}} method only checks for reference 
> equality before falling back to the {{AbstractBlob.equals()}} method that 
> just scans the entire byte stream.
> This works well for the majority of cases where a binary won't change at all 
> or at least not often. However, there are some cases where a client 
> frequently updates a binary or even rewrites it with the exact same contents. 
> We should optimize the handling of also those cases.
> Some ideas on different things we can/should do:
> # Make {{AbstractBlob.equals()}} compare the blob lengths before scanning the 
> byte streams. If a blob has changed it's length is likely also different, in 
> which case the length check should provide a quick shortcut.
> # Keep a simple checksum like Adler-32 along with medium-sized value records 
> and the block record references of a large value record. Compare those 
> checksums before falling back to a full byte scan. This should capture 
> practically all cases where the binaries are different even with equal 
> lengths, but still not the case where they're equal.
> # When updating a binary value, do an equality check with the previous value 
> and reuse the previous value if equal. The extra cost of doing this should 
> get recovered already when the commit hooks that look at the change won't 
> have to consider an unchanged binary.



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