Hello everybody,
This is from man pam_unix:
> try_first_pass
> Before prompting the user for their password, the module first
> tries the previous stacked module's password in case that satisfies this
> module as well.
I think pam_oath has a similar option.
So I tested with these in my pam configuration:
auth sufficient pam_unix.so
-auth required pam_oath.so usersfile=/etc/users.oath digits=6 try_first_pass
and
-auth sufficient pam_oath.so usersfile=/etc/users.oath digits=6
auth required pam_unix.so try_first_pass
My understanding is that I get one prompt that accepts unix and oath
password. But obviously this does not work, authentication fails for the line
containing try_first_pass.
Anything I misunderstood? How is this expected to work?
--
main(a,b){char*/* Schoene Gruesse */c="B?IJj;M"
"EHCX:;";for(a/* Chris get my mail address: */=0;b=c[a++];)
putchar(b-1/(/* gcc -o sig sig.c && ./sig */b/42*2-3)*42);}
