Em 16/8/2003, 00:37, Luiz ([EMAIL PROTECTED]) disse:

> lim(1+k/n)^n=e^k. com n no inf. Isso e verdade ????
> Alguem tem uma dem. disso ?

k/n = 1/a  => n = ka

lim[n->inf] (1 + k/n)^n
lim[a->inf] (1 + 1/a)^(ka)
lim[a->inf] ((1 + 1/a)^a)^k) = e^k

Ateh


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 Cria��o: 16/8/2003 (01:22)
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