sen(x-110)=sen(x-90-20)=sen-((20-x)+90)=-sen((20-x)+90)=-cos(20-x)=p logo cos(20-x)=-p
From: [EMAIL PROTECTED] Reply-To: [email protected] To: [email protected] CC: [EMAIL PROTECTED] Subject: [obm-l] Probleminhas faceis que n�o saio.. Date: Sun, 20 Feb 2005 11:01:49 EST
1) Sen(x-110�) = p, o valor de cos (20-x) �:
a) p b)- p c ) p/2 d) 0 e ) 1
2) Se x E |R a equa��o :
tg2k x tg3k =1
tem quantas solu��es no intervalo [ 0, 2pi]
a) 5 b) 6 c) 8 d) 9 e) 10
3) F(x) = senx - sen11x/ sen 14x + sen2x calcule f(pi/13)
a) -1 b) 1 c) 0 d) 1/2
ab�os Junior
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