Hi list,
I've got a test document (a grayscale PNG) which has a white bg.
Trying to segment it using other methods beside RAST fails.
(1) Error:
ocroscript: segmenter.lua:24: CHECK ./ocr-utils/ocr-utils.cc:833
background_seems_white(a)
stack traceback:
[C]: in function 'segment'
segmenter.lua:24: in main chunk
[C]: ?
segmenter.lua:
20 --segmenter = make_SegmentPageByRAST(); --works
21 --segmenter = make_SegmentPageByXYCUTS(); --needs binary image. fail (2)
22 --segmenter = make_SegmentPageBy1CP(); --fail (1)
23 segmenter = make_SegmentPageByMorphTrivial(); --fail (1)
24 segmenter:segment(seg,image); -- fails (1) & (2)
25 check_page_segmentation(seg);
Lines from ocr-utils/ocr-utils.cc:
831 void optional_check_background_is_lighter(colib::bytearray &a) {
832 if(bgcheck) {
833 CHECK_CONDITION(background_seems_white(a));
834 }
835 }
So, my question is why does it matter if the bg is white and why the
check in place?
I _could_ possibly set bgcheck = false, recompile and get away with
it. But I somewhat fail to understand what the motivation is. Could
someone please enlighten me before I step on a giant monster and get
killed?
(2) A binarize'd image was provided but then
"check_page_segmentation(seg)" crushed it right away:
ocroscript: segmenter.lua:39: CHECK
./ocr-utils/ocr-segmentations.cc:275 (column > 0 && column < 32) ||
column == 254 || column == 255
stack traceback:
[C]: in function 'check_page_segmentation'
segmenter.lua:39: in main chunk
[C]: ?
The binarize'd image was provided using:
28 input = bytearray();
29 iulib.read_image_gray(input,arg[1]);
30 binarizer:binarize(image,input);
Why?
Thanks loads.
--
Regards,
Ishwor Gurung
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