Hello
When we perform
>a(b)
Octave engine acts in the following manner:
1 create an empty array ,say "temp",with its size equals size(b)=[1 4]
2 temp(1)=a(b(1))
3 temp(2)=a(b(2))
4 temp(3)=a(b(3))
5 temp(4)=a(b(4))
when we perform a(b)++ current implementation of Octave,that ignores
repetitions, acts:
1 temp=unique(b)
2 a(temp)++
this means a(2)++ thus 'a' becomes [4 6 6]
but if it behave in efficient way it acts:
1 a(b(1))++ that equals a(2)++ and because a(2) was 5 then we have a=[4
6 6]
2 a(b(2))++ that equals a(2)++ and because a(2) was 6 then we have a=[4
7 6]
3 a(b(3))++ that equals a(2)++ and because a(2) was 7 then we have a=[4
8 6]
4 a(b(4))++ that equals a(2)++ and because a(2) was 9 then we have a=[4
9 6]
this efficient way is very useful for creating 'histograms'.
Thanks,
Hossein
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