On Wed, Nov 17, 2010 at 10:41 AM, Eduardo D. da Costa <zyx...@gmail.com> wrote:
> Dear Alexander,
>
> Thanks for your octcdf package that is allowing me to to use octave in my
> new job. Before I used mainly matlab.
> In the  file example_netcdf.m that comes with your package there is an
> example how to read a netcdf file :
>
> %---------------------------------------%
> %                                       %
> % read data from a netcdf file          %
> %                                       %
> %---------------------------------------%
>
> nc =3D netcdf('example.nc','r');                       % open netcdf file
> example.nc in read-only
>
> n =3D nc('longitude');                                 % get the length of
> the dimension longitude
>
> temp =3D nc{'temp'}(:);                                % retrieve the netcdf
> variable temp
> temp_units =3D nc{'temp'}.units;                       % retrieve the
> attribute units of variable temp
> temp_valid_range =3D nc{'temp'}.valid_range;           % retrieve the
> attribute valid_range of variable temp
>
> global_history =3D nc.history;                         % retrieve the global
> attribute history
>
>
>
> However if you wish to get (not the length of the dimension longitude) but
> the longitude values themselves, how do you proceed ?


try this:

LON = nc{'longitude'}(:);

(notice the curly brackets)

Cheers,
Alex


> I tried octave3:34> LON =3D nc('longitude')(:) and get LAT =3D  360
> What I expected was to obtain  LAT =3D-90 -89 -88 ... 89 90
>
> Thanks in advance for your help. My boss is asking for the pictures and your
> help would be very much appreciated.
>
> Best regards
>
> Eduardo
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Spend less time writing and  rewriting code and more time creating great
experiences on the web. Be a part of the beta today
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