I am afraid, I am not sure how to code/ compute it...

On 12-10-30 5:08 PM, "Juan Pablo Carbajal" <ajuanpi+...@gmail.com> wrote:

>On Tue, Oct 30, 2012 at 3:03 PM, Surandokht Nikzad <surando...@gmail.com>
>wrote:
>> Hi there,
>>
>> I am beginner in Octave.
>> I am using this for calculation kernel density for some concentrations.
>>
>> This is one example data:
>>
>> ssw ef
>> 1.85 1.497297297
>> 1.21 1.719008264
>> 1.44 1.451388889
>> 1.71 1.514619883
>> 1.4         1.192857143
>> 0.396 1.795454545
>>
>> Here is the codes:
>>
>> doc_ef=a(:,2);
>> doc_ssw=a(:,1);
>> run_doc=0:d:20;
>> dens_est_doc_ef=kernel_dens(ones(size(run_doc)),doc_ef,run_doc);
>> plot(run_doc,dens_est_doc_ef,'b')
>>
>> The integral of each distribution should be equal to one!My question is
>>how
>> can I avoid having plots over one in my graph. The example for graph is
>> attached by this email.
>>
>> Any idea and suggestion would be appreciated.
>>
>> Thanks,
>> Sue
>>
>> 
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>
>As you said the integral of probability density function is one, but
>the density function itself could be bigger then one. Think of the
>delta distribution.
>http://en.wikipedia.org/wiki/Delta_distribution
>
>If you want, you can plot the normalized frequency plot using hist
>with the normalization argument equal to 1.



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