Hi Robert
If you're using PHP 5, use type hinting.
class tSecurity
{
public function __construct(tDatabase $ADatabase)
{
$this->database=$ADatabase;
}
}
Todd
> Hi
>
> I have a class (tDatabase) that I create and pass into another Class
> (tSecurity) and use in it.
>
> My IDE does code prompting / completion on the $database instance when
> in the same function where it is created ($database = new tDatabase)
> however within my tSecurity class I cant as it doesn't know that
> $this->database (set in constructor, $security = new
> tSecurity($database)) is of type tDatabase. Is there a way to flag a
> class property is a specific data type so that my code completion can work ?
>
> Cheers
> Rob
>
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