I think you had a slight issue with the syntax for specifying the optional
values. You want this:
oiotool -pattern fill:color=0.2,0.3,0.4 128x128 3 -o tmp.exr
Also valid is to create an empty image, then execute the fill command on its
full extent:
oiiotool -create 128x128 3 -fill:color=0.2,0.3,0.4 128x128+0+0 -o
tmp.exr
The fill pattern is lets you also do horizontal, vertical, or 4-corner color
gradients as well:
oiiotool -pattern fill:left=0.2,0.3,0.4:right=1,0,0 128x128 3 -o tmp.exr
oiiotool -pattern fill:top=0.2,0.3,0.4:bottom=1,0,0 128x128 3 -o tmp.exr
oiiotool -pattern
fill:topleft=1,0,0:topright=0,1,0:bottomleft=0,0,1:bottomright=0,1,1 128x128 3
-o tmp.exr
> On Jun 2, 2016, at 12:30 PM, Andrea Solis <[email protected]> wrote:
>
> Hi,
> I'm trying to create an image filled with a specified color. I'm able to
> successfully create a black image usiing this command:
> oiiotool --pattern fill 128x128 3 -o /tmp/test.exr
>
> But I can't figure out the syntax for specifying a fill color. I've tried
> this:
>
> oiiotool --pattern fill=1.0,0,0 128x128 3 -o /tmp/test.exr
>
> It doesn't work, the resulting image is still black. Anything else I've
> tried results in a syntax error.
>
> Is this a bug or am I formatting the command incorrectly? I'm using
> openimageio version 1.6.13
>
> Thanks,
> Andrea
>
>
>
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--
Larry Gritz
[email protected]
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