Thanks Rick, but from .directory upwards the inheritance chain isn't it:
.directory -> .MapCollection -> .Collection
So what about this in section 5.3.19:
If argument is a MapCollection, then index values are used to determine
membership, and items are
inserted into the result using the index and item pairs.
Ruurd
On 21-8-2013 0:46, Rick McGuire wrote:
What you are missing is the act of coercing the source collection into
a compatible type (this is described in section 5.3.19 The Concept of
Set Operations). In this situation, the items are used to integration
with the set. If you wish to merge the indexes, then
source~allindexes as an argument for the merge.
Rick
On Tue, Aug 20, 2013 at 5:19 PM, Ruurd Idenburg <ru...@idenburg.net
<mailto:ru...@idenburg.net>> wrote:
This is the description of set~intersection:
5.3.14.4. intersection
>>-intersection(argument)--------------------------------------><
Returns a new collection (of the same class as the receiver)
containing only those items from the receiver
whoseindexes are in both the receiver collection and the argument
collection. The argument can be any
collection class object. The argument must also allow all of the
index values in the receiver collection.
and I think this is the code for set~intersection in CoreClasses.orx:
::METHOD intersection -- take the intersection of
sets
use strict arg other -- get the companion object
signal on nomethod
new = self~class~new -- use a new instance
if other~isA(.Collection) then
values = other~allitems -- get all of the items from the other
collection
else
values = other~makearray -- ask for an array version
of the source
count = values~items
do i = 1 to count
index = values[i]
-- if we have one of these, put into the result
-- NB: Since this is a SET, there will only be one copy
accumulated.
if self~hasindex(index) then
new~put(index)
end
return new -- return the difference
collection
nomethod: -- unknown method sent
raise syntax 93.948 array(1, "Collection")
In my case the other collection is a .directory, where items and
indexes are not necessarily the same.
What am I misunderstanding?
-- Ruurd Idenburg
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