On Fri, Nov 29, 2013 at 11:17 AM, Staffan Tylen <staffan.ty...@gmail.com>wrote:
> I'm playing around with the date() function and am trying to convert a
> date in the format yyddd to yymmdd but I can't find a way to handle the yy
> portion of the date. The "D" option supports the ddd portion but the result
> shows the current year. How can I make yy be part of the calculation?
>
Hi Staffan,
I'm not much help here, dates are too complex for me. If I can figure out
today's date, I'm about at my limit.
My first thought though is that the DateTime class may be of more help than
the date() function.
--
Mark Miesfeld
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