Do you ever specify a seed value with a prior random call? That would
force a repeatable sequence. Other than that, I'd need a program that
reproduces the problem to figure this out.
Rick
On Sat, Apr 19, 2014 at 10:38 AM, Staffan Tylen <staffan.ty...@gmail.com>wrote:
> I have the following code in an application (where pfxlen already has been
> set to 4):
>
> pfx = ""
> do pfxlen
> pfx ||= xrange("00"x,"7F"x)~substr(random(1,127),1)
> end
>
> But when I run the application, pfx is always generated with the same
> value: BNB" or '424E4222'x - but it should be random!
>
> To debug this I lifted this code snippet to a test program, adding
> pfxlen=4 as the first instruction, and then pfx gets different values each
> time, as expected.
>
> When I do a 'trace i' I can see that random(...) is returning the same
> value sequence each time when running the code in the application: 67, 79,
> 67, 35. When I run the test program it always returns different values.
>
> OK, so I change the program to this:
>
> pfx = ""
> do pfxlen
> rand = random(1,127)
> pfx ||= xrange("00"x,"7F"x)~substr(rand,1)
> end
>
> No change, the same values are returned. So then I try this:
>
> pfx = ""
> do pfxlen
> say random(1,127)
> pfx ||= xrange("00"x,"7F"x)~substr(random(1,127),1)
> end
>
> Now pfx gets the value N";* ('4E223B2A'x) but also now it gets the same
> value EVERY time.
>
> I can only conclude that there must be a bug in the random() function that
> seems to introduce a seed on its own under certain circumstances, is that
> possible? I cannot explain this behaviour in any other way.
>
> Staffan
>
>
>
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