> | I mean that if I can write:
> | 
> |   y := x + 1
> | 
> | and expect the compiler to provide an implicit type for y based on
> | knowledge of x, + and 1 where all of these potentially overloaded, the
> | number of possibilities rises rapidly. The greater the number of
> | possibilites, the greater that chance of making a type error.
> 
> what is the fundamental difference with
> 
>    y := x() + One()
> 
> ?

Gaby, I don't understand your question. Be more specific.

Ralf

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