On Wed, Jul 9, 2008 at 12:22 AM, Bill Page <[EMAIL PROTECTED]> wrote: > The multiplication of a Float and some unknown symbolic value must > produce a symbolic expression of some kind. If we know that the > currently unknown symbolic value can only take values from Float, > then we can deduce from knowledge of multiplication in Float that > the value of the symbolic expression representing the multiplication > of a Float with this unknown symbolic value must also only take > values from Float.
This is a fundamental observation. The way I read x: Float x + 1 is hat the declaration x:Float asserts that x can only take Float values, when it has a value. -- Gaby ------------------------------------------------------------------------- Sponsored by: SourceForge.net Community Choice Awards: VOTE NOW! Studies have shown that voting for your favorite open source project, along with a healthy diet, reduces your potential for chronic lameness and boredom. Vote Now at http://www.sourceforge.net/community/cca08 _______________________________________________ open-axiom-devel mailing list open-axiom-devel@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/open-axiom-devel