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https://issues.apache.org/jira/browse/OPENJPA-236?page=com.atlassian.jira.plugin.system.issuetabpanels:comment-tabpanel#action_12494086
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Abe White commented on OPENJPA-236:
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One-way inverse-key-based relations are not a typical case, given that they
aren't even supported in standard JPA. You might need to use a custom field
mapping in conjunction with the custom class mapping.
> No apparent way to generate all required SQL within a class derived from
> FullClassStrategy
> ------------------------------------------------------------------------------------------
>
> Key: OPENJPA-236
> URL: https://issues.apache.org/jira/browse/OPENJPA-236
> Project: OpenJPA
> Issue Type: Bug
> Components: kernel
> Affects Versions: 0.9.7
> Reporter: David Ezzio
> Attachments: OpenJPABugCustomSQL.zip
>
>
> FullClassStrategy has several optional methods for overriding OpenJPA's
> generation of SQL. However, in a simple case, there is no apparent way to
> generate the required SQL within a class derived from FullClassStrategy.
> The model consists of two classes, BizA which has a one-way, one-to-many
> relationship to BizB. The relationship is mapped with an inverse key within
> the BizB table.
> The custom class strategy BizBMapping attempts to insert a BizB record and is
> able to do so, provided that it is not contained within a BizA collection.
> Otherwise, the attempt to persist a BizA with a contained BizB yields a SQL
> exception because OpenJPA generates additional SQL that conflicts with the
> SQL generated within BizBMapping.customInsert. Even if OpenJPA did not
> generate conflicting insert statement, there is no apparent way to get the
> value for the A_ID column within the BizBMapping.customInsert method.
> This issue is critical for users who want to substitute their own SQL (such
> as calls to stored procedures) for all of the OpenJPA generated SQL.
> Synopsis of the output log:
> INSERT INTO BIZB (ID, INFO) VALUES (?, ?) [params=(String) B22047141,
> (String) random]
> INSERT INTO BizA (id, info) VALUES (?, ?) [params=(String) A32968849,
> (String) random]
> INSERT INTO BizB (A_ID) VALUES (?) [params=(String) A32968849]
> SQLException: Column 'ID' cannot accept a NULL value.
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