On 11/8/18 11:25 AM, Ivan Vodišek wrote:
By definition, NP-complete problems are such NP problems to which any other NP problem can be reduced in polynomial time. There are proven numerous NP-complete problems (Boolean SAT and Traveling salesman being some of them), and if we would solve any of them, we would automatically cover the whole set of NP.

True.

When I say subclass of inputs, I literally mean inputs, so if say f is
a function in NP, there is some subclass of x, S, such that for all x
in S, T(f(x)) = O(|x|^n). An obviously subclass would be where |x| is
bound, but that's of course not interesting.

Or one could consider the complexity over a sequence of inputs, where
only incremental costs are considered.

I guess it means that there are multiple ways to crack P = NP other
than in its full generality that can still be useful.

Nil


čet, 8. stu 2018. u 07:17 'Nil Geisweiller' via opencog <[email protected] <mailto:[email protected]>> napisao je:

    Hello,

    On 11/7/18 4:44 PM, Ivan Vodišek wrote:
     > My approach is to manually resolve some NP complete
     > <https://en.wikipedia.org/wiki/NP-completeness> problems such are
     > Boolean SAT or Traveling salesman in polynomial time. I have some
     > indices that it is a possible task.

    I suspect you'd only discover subclasses of inputs for which P = NP.
    But that doesn't mean it wouldn't be useful or insightful.

     > (My apologies to Singularity.net
     > crew due to mess that P = NP would do to AGI Coin. But there are
    so much

    Quite the contrary, any knowledge that can be used to decrease
    algorithmic complexity is extremely welcome. Consider that you're
    talking to people who are banging their heads against the wall of
    complexity on a daily basis. ;-)

    Nil

     >
     >
     >     Obviously for a finite set of inputs, one can turn any complex
     >     algorithm into a logarithmic one (think of a pre-calculated
    binary
     >     decision tree, where each branch is a bit describing the
    input and
     >     each leaf is the solution). But it should still be possible
    to learn
     >     an actual algorithm rather than a finite giant decision tree,
    that
     >     performs worse that log, is more compact, but performs better
    than NP
     >     for a bunch of real-world problems.
     >
     >
     > I think of algorithms as a possible compressed forms of their output.
     >
     > sri, 7. stu 2018. u 14:19 'Nil Geisweiller' via opencog
     > <[email protected] <mailto:[email protected]>
    <mailto:[email protected] <mailto:[email protected]>>>
    napisao je:
     >
     >     Hello Ivan,
     >
     >     If P = NP it would mean that, given a problem reframed as
    reasoning
     >     such that its solution is a proof p of size s, one could
    construct p
     >     in a polynomial time of s, which sounds very doubtful.
     >
     >     That's in theory, in practice however I think we could make P
    = NP for
     >     some class of inputs via clever use of meta-learning (such as
     >     inference control meta-learning that we're experimenting within
     >     opencog, see
     >
    
https://blog.singularitynet.io/introspective-reasoning-within-the-opencog-framework-1bc7e182827).
     >
     >     In fact I had this dream where we could have a sequence of NP
    problems
     >     and progressively learn how to solve them in P.
     >
     >     Obviously for a finite set of inputs, one can turn any complex
     >     algorithm into a logarithmic one (think of a pre-calculated
    binary
     >     decision tree, where each branch is a bit describing the
    input and
     >     each leaf is the solution). But it should still be possible
    to learn
     >     an actual algorithm rather than a finite giant decision tree,
    that
     >     performs worse that log, is more compact, but performs better
    than NP
     >     for a bunch of real-world problems.
     >
     >     Nil
     >
     >     On 11/6/18 7:00 PM, Ivan Vodišek wrote:
     >      > Hello everyone :)
     >      >
     >      > I have a question regarding to my independent research
    relating to
     >      > OpenCog. I read somewhere (I really don't remember where)
    that if
     >     P = NP
     >      > <https://en.wikipedia.org/wiki/P_versus_NP_problem> then
    it would be
     >      > beneficial to AI in general.
     >      >
     >      > There are science fields which would obviously benefit if
    P = NP.
     >     But my
     >      > question is: how would specifically OpenCog benefit from that
     >     solution?
     >      > Somehow, it should be a matter of reducing a large number of
     >     possible
     >      > combinations, but I don't really see were would AI fit
    into this
     >      > equation. Googling around didn't produce anything
    interesting, so
     >     I'm
     >      > making a post to this OpenCog community in a hope for an
    answer.
     >      >
     >      > Thank you all for your time,
     >      > Ivan V.
     >      >
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