I'm working with a transformed map object (NPoleOrtho), so the coordinates aren't in degrees. I am able to feed to Camera the range of these coordinates whatever they are (I didn't really realize this when I posted this question), and get a fairly reasonable view.
The real problem I'm having in sizing the window now is the polar-projected map. This is not really a Camera question any more, I don't think, it is a projection question. When I subset a cartesian map by lon/lat to get the region of interest, make a polar projection of the result, and then overlay this with the polar-projected data, there is too much map extending south in relation to the data. This extra map area takes needed window real estate. It seems that for a regional polar map created this way, the min latitude (which determines the southern boundary) that I input to WorldMap-projections needs to be greater than it would be for a rectangular map, in order to avoid unnecessary map. I am guessing at some value (10% of the range, or something like that), but it would be nice if I had some kind of formula to get it just right. Does this sound like the result that you would expect to see if subsetting a rectangular map, then polar-projecting it ? On Mar 27, 8:21pm, Lloyd A Treinish wrote: > Subject: Re: [opendx-users] Camera view for polar projection > > Given DX's cartesian camera, a full hemisphere view will have a width of > 180 for that projection. If the aspect < 1, it will cut off the top and > bottom. So, you should adjust for aspect or having the window bigger to > accommodate legends, etc. > > > "Sharon Cady" <[EMAIL PROTECTED]>@opendx.watson.ibm.com on > 02/15/2001 12:22:05 PM > > Please respond to [email protected] > > Sent by: [EMAIL PROTECTED] > > > To: [email protected] > cc: > Subject: [opendx-users] Camera view for polar projection > > > > Lloyd or others, > > I'd like to define a camera which will automatically set the appropriate > view > to zoom in on a specified chunk of data which has been polar projected > (N-Pole-Ortho). With a rectangular projection, I can just set the camera > view > to be some % > the longitude range. But this does not work to size the > polar > projected data. > > Thanks, > > Sharon > > >-- End of excerpt from Lloyd A Treinish
