"Gregory D Abram" <[EMAIL PROTECTED]> writes: > > If you are dealing with surface elements - eg. quads and triangles, and > you are rendering smooth surfaces, I'd give serious thought to Lloyd's > solution - the overhead of converting quads to triangles is probably worth > the C1 continuity that you get. Visible partition boundaries suck. > > Greg
When I used DX some time ago, it appeared to me that DX does a decomposition of quadrangles in triangles anyhow, i.e. they didn't use a bilinear interpolation on quadrangles. Is that correct? And can that behaviour be enhanced? Nicolas.
