Hi,
If X1 represents the 8x3 matrix of the first cube corner positions
and X2 the second one, at each intermediate time between 0 and 1
you can linearly interpolate the cube position by
X = X1*(1-t) + X2*t
I am not expert enough in opendx to tell you how to implement it,
but my guess is to have a box with the initial X1, another one with X2
and a compute box function of t calculating X.
Dan
Juw Won Park wrote:
Hi all.
The file I describe here has 16 points.
First 8 points represent original cube and second 8 points represent
moved cube. 1st,2nd, and 3rd column represents x,y,and z respectively.
4th column represents time. Here I have only two values, time0 and
time1.
==================
0 0 0 0
1 0 0 0
1 0 1 0
0 0 1 0
0 1 0 0
1 1 0 0
1 1 1 0
0 1 1 0
1 1 1 1
2 1 1 1
2 1 2 1
1 1 2 1
1 2 1 1
2 2 1 1
2 2 2 1
1 2 2 1
===================
When I import it, it shows original cube and I stuck right there :(
How can I change time (in other word, animate) to show moved cube?
I imported it as scattered data, with 2 variables. One is location
3-vector, and the other is time scalar.
Any comment would be appreciated.
Regards,
Juw Won Park
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Prof. Daniel Pfenniger
Geneva Observatory, University of Geneva
CH-1290 Sauverny, Switzerland
[EMAIL PROTECTED] | tel:+41 (22) 7552611 | fax:+41 (22) 7553983
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