From: Ross Burton <[email protected]> If the function a ThreadedWorker is executing raises an exception, don't use print() as that mostly disappears. Instead, output it to the logger.
This is done using bb.mainlogger.debug directly instead of bb.debug() as this allows us to pass the exception instance directly, which is then incorporated into the log stream. Signed-off-by: Ross Burton <[email protected]> Signed-off-by: Richard Purdie <[email protected]> (cherry picked from commit 2f1ea25c222b344dd8b784b2bc73a6540ab30274) Signed-off-by: Anuj Mittal <[email protected]> --- meta/lib/oe/utils.py | 3 ++- 1 file changed, 2 insertions(+), 1 deletion(-) diff --git a/meta/lib/oe/utils.py b/meta/lib/oe/utils.py index a84039f585..2a8771dc28 100644 --- a/meta/lib/oe/utils.py +++ b/meta/lib/oe/utils.py @@ -480,7 +480,8 @@ class ThreadedWorker(Thread): try: func(self, *args, **kargs) except Exception as e: - print(e) + # Eat all exceptions + bb.mainlogger.debug("Worker task raised %s" % e, exc_info=e) finally: self.tasks.task_done() -- 2.31.1
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