* silly solution to filter multiple versions shown in installed-packages.txt 
where one is with Status not-installed and the right one with installed
* someone with better idea?

Signed-off-by: Martin Jansa <[email protected]>
---
 classes/testlab.bbclass |    2 +-
 1 files changed, 1 insertions(+), 1 deletions(-)

diff --git a/classes/testlab.bbclass b/classes/testlab.bbclass
index bc6b6e5..b8ba9fe 100644
--- a/classes/testlab.bbclass
+++ b/classes/testlab.bbclass
@@ -36,7 +36,7 @@ if [ -e  ${IMAGE_ROOTFS}/etc/opkg ] && [ 
"${ONLINE_PACKAGE_MANAGEMENT}" = "full"
        echo -e "digraph depends {\n    node [shape=plaintext]" > 
${TESTLAB_DIR}/depends.dot
 
        for pkg in $(opkg-cl ${IPKG_ARGS} list_installed | awk '{print $1}') ; 
do 
-               opkg-cl ${IPKG_ARGS} info $pkg | awk '/^Package/ {printf $2"_"} 
/^Version/ {printf $2"_"} /^Archi/ {print $2".ipk"}'  >> 
${TESTLAB_DIR}/installed-packages.txt
+               opkg-cl ${IPKG_ARGS} info $pkg | grep -B 7 -A 7 "^Status.* 
\(\(installed\)\|\(unpacked\)\)" | awk '/^Package/ {printf $2"_"} /^Version/ 
{printf $2"_"} /^Archi/ {print $2".ipk"}'  >> 
${TESTLAB_DIR}/installed-packages.txt
 
                for depends in $(opkg-cl ${IPKG_ARGS} info $pkg | grep 
^Depends) ; do 
                        echo "$pkg OPP $depends;" | grep -v "(" | grep -v ")" | 
grep -v "$pkg OPP Depends" | sed -e 's:,::g' -e 's:-:_:g' -e 's:\.:_:g' -e 
's:+::g' |sed 's:OPP:->:g' >> ${TESTLAB_DIR}/depends.dot
-- 
1.7.1


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