In line 91 of the diff, you can replace v[0] by a randomized choice function:
repl = lambda m: random.choice(v)
s = re.sub(k, repl, s, flags=re.IGNORECASE)
And you may optimize it by:
- pre-compiling regular expressions in the dictionary
- replacing lists in translations by the function above
REPL = dict([(re.compile(k), lambda m: random.choice(v) if isinstance(v, list)
else v) for k, v in REPL.iteritems()])
Raphael ;-)
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