>How is the framebuffer memory organized? e.g. if I open /dev/fb0,
>mmap it and try to draw stuff, is each pixel 18 bits, or 3 bytes
>aligned in a particular way?
It sort of funky. Here's a couple of macros:
#define xze2_writeRGBpixelTo666(p,R,G,B) { p[0]=((G&0x0C)<<4)|(B>>2);
p[1]=((R&0x3C)<<2)|((G&0xF0)>>4); p[2]=R>>6; }
#define xze2_writeRGBpixelTo666inc(p, R, G, B) { *p=((G&0x0C)<<4)|(B>>2); p++;
*p=((R&0x3C)<<2)|((G&0xF0)>>4); p++; *p=R>>6; }
Where 'p' is a unsigned char pointer to the framebuffer memory, and R, G, and B
are 0-255 values. (Each pixel is 3-bytes. Pixels are contiguous row to row.)
-Pat
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