I just use loadURL for this sort of thing, eg.
OpenLayers.loadURL ('script.php', parameters, null, successCallback,
failureCallback );
Then in the successCallback you could do something like (assuming you're using
the Prototype library,
I'm not sure whether openlayers has its own json evaluation function but this
is how you do it with
prototype):
function successCallback(xmlhttp)
{
var json = xmlhttp.responseText.evalJSON();
...
}
Also is there a need for the php to be fetching the json from another file? You
could just generate the json directly from the php as follows (apologies if I'm
misunderstanding what you're trying to do....)
<?php
header("Content-type: application/json");
$dataToBeEncoded = [set up your data structure];
echo json_encode($dataToBeEncoded);
?>
Nick
[email protected] wrote: -----
To: [email protected]
From: [email protected]
Sent by: [email protected]
Date: 07/11/2011 10:05PM
Subject: [OpenLayers-Users] help with passing a var from OL to PHP
hi,
I have a simple base map and I'm clicking the map to retrieve the lat/lons that
will be fed into a url to retrieve a json file. I'm having trouble returning
the url I want to send via PHP. I'm almost certain the problem is in the
OpenLayers.Request but the docs and examples haven't helped me through this
one. Can anyone see what my problem is here?
Thanks in advance!
Relevant parts of code below:
.....
map.events.register("click", map, function(e) {
var position = map.getLonLatFromPixel(e.xy);
position.transform(new OpenLayers.Projection("EPSG:900913"), new
OpenLayers.Projection("EPSG:4326"));
var mouselat = position.lat;
var mouselon = position.lon;
var geturl =
'http://locationofthejson.com/'+mouselat+','+mouselon+'.json';
// console.log(geturl); This prints the url ok!
var request = OpenLayers.Request.POST({
url: "http://localhost:8888/mypage.php";,
data: geturl,
headers: {
"Content-Type": "text/plain"
},
success: function(request) {
alert(request.responseText);
}
});
});
<?php
if (isset($_GET['geturl'])) { $get_url = $_GET['geturl'];}
$json_string = file_get_contents($get_url);
$parsed_json = json_decode($json_string);
echo 'console.log("'.$get_url.'");'; // Nothing returned here!
?>
_______________________________________________
Users mailing list
[email protected]
http://lists.osgeo.org/mailman/listinfo/openlayers-users
_______________________________________________
Users mailing list
[email protected]
http://lists.osgeo.org/mailman/listinfo/openlayers-users
