Hi, for a single file, I can specify the desired name of the file as part of the “inputFiles” declaration. But how can I do this if the input files variable is an array from an aggregation ? The reason I need this is because the external program that processes the input files (i.e., to compute an average image given the individual result images of the exploration), requires the files to have a proper file name extension.
val f = Val[File] val explore = ExplorationTask(f in SelectFileDomain(…)) val average = ScalaTask(“…”) set (inputFiles += (f.toArray, “???”)) val ex = explore -< Capsule(EmptyTask(), strainer = true) >- average Cheers, Andreas
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