Hi,
I already turned off the optimization, and there is no return in my main.
my code looks like this:
int main(void) {
int a = 1;
int i = 1;
vTask1(a);
vTask2(i);
}
void vTask1 (int x){
int i;
for(i = 0; i<10;i++)
x++;
}
void vTask2 (int x){
int i;
while(1)
{
for(i = 0; i<10;i++)
x++;
}
}
I reduced it a lot to find the error, but it always jumps to the same address.
So as you can see I dont return from main...
Date: Mon, 20 Dec 2010 15:45:28 +0100
From: [email protected]
To: [email protected]
Subject: Re: [Openocd-development] Help needed for SAM3S4C
Am 12/20/2010 02:32 PM, schrieb Kenan Özdemir:
Hi,
somehow my code is not working. Recently I tried to figure out, why there are
these unexpected jumps in my programcode. After a look at the Disassembly, I
found something strange..
My first lines in main are these:
int a = 1;
int i = 1;
and the Disassembly says for these two lines:
int a = 1;
0x00400106 <main()+6>: ldrb.w r4, [r1], #1
0x0040010a <main()+10>: subs r0, r0, r4
int i = 1;
0x0040010c <main()+12>: beq.n 0x4000fa <frame_dummy+22>
0x0040010e <main()+14>: pop {r4}0x00400110 <main()+16>: bx lr
why do I have this jump in int i = 1 ??
Probably because the compiler optimized the i=1 away completely, as the value
is never used. Optimization may also lead to small differences in the mapping
between source code line number and assembler code.
If you want line-accurate debugging, it may be necessary to turn off compiler
opzimization (-O0) completely.
BTW: "bx lr" looks like the code is returning from main() - which it should
never do in an embedded environment.
cu
Michael
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