Oh and i forgot. The nasty thing is that if i store like the first 50 friends, and have 10 per page, then every time i change page and try to get the data, i will loop through the first 10, ou 20, or.. i get the picture.
On Feb 27, 2:33 pm, Pedro Vicente <neteinst...@gmail.com> wrote: > I knew that way, but thought that there was a "nicer" or "cleaner" > way. > > Tks > > On Feb 27, 2:26 pm, Robson Dantas <biu.dan...@gmail.com> wrote: > > > Hi Pedro. > > > The simplest way is to use a variable to count first five and then exit. > > > var i=1; > > xpto.each(function(person){ > > > if (i==5) return; > > > do stuff.. > > > i++; > > > }); > > > Let me know if it is what you want. > > > Cheers, > > > --Robson Dantashttp://blogdodantas.dxs.com.br > > > 2009/2/27 Pedro Vicente <neteinst...@gmail.com> > > > > Hello, > > > > I've been looking at some examples of apps in hi5 and OpenSocial page. > > > > All of them make a request of 10 friends for example, and then with > > > the xpto.each(function(person) { .... use them all. > > > > My question is, how do i get only the 5 first friends of the 10 (so > > > that i can request a X ammount of friends and do some pages with them > > > without having to do a cycle with all of them... > > > > Thanks in advanced and sorry if the is a more javascript question. --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "OpenSocial Application Development" group. To post to this group, send email to opensocial-api@googlegroups.com To unsubscribe from this group, send email to opensocial-api+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/opensocial-api?hl=en -~----------~----~----~----~------~----~------~--~---