Hi John,

This question is probably more appropriate for mdb-discuss, but to answer:

On SPARC we always give you the values of the 8 input registers in order 
from 0 to 7. You should just pay attention to the first value in this case.

Adam

On Mon, Sep 17, 2007 at 06:45:58PM +0800, xiong xiaoyi wrote:
> Hi  experts,
> 
> I have a simple problem on mdb debugging, I use mdb to debug a core,
> 
> > $C
> ffbfde18 libc.so.1`realfree+0x40(90c58, ef012eef, ff000000, a90fc, 0,
> ff362a00)
> ffbfde78 libc.so.1`cleanfree+0x58 (0, 4, ff01b6b8, ff012620, a885c, 1)
> ffbfded8 libc.so.1`_malloc_unlocked+0x104(8, ef012eec, 90c50, ef012eef,
> 1c00,
> ff19e5c0)
> ffbfdf38 libc.so.1`malloc+0x48(8, 1cc4, 1, ff012620, a9824, ff01ca2c)
> ffbfdf98 libc.so.1`calloc+0x58 (8, 8, 8, 10, 30, 30)
> ffbfdff8 libnsl.so.1`thr_get_storage+0x40(ff22e440, 8, 5ce70, 59c2c, 0, 0)
> 
> In above stack, it prints function's argument, but the number of the
> arguments is not same as the function definition.
> For example, in mdb, we get:
> 
>        ffbfdf38 libc.so.1`malloc+0x48(8, 1cc4, 1, ff012620, a9824, ff01ca2c)
> 
> But the molloc definition is :
> 
>        malloc(size_t size)
> 
> So from the mdb output above, how can I know what's the size in malloc?
> Thanks in advance.
> 
> Thanks,
> John

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-- 
Adam Leventhal, FishWorks                        http://blogs.sun.com/ahl
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