From: Jake <[EMAIL PROTECTED]>
Perfectly normal, it's called normalising. The bignum as well as the
"bin" are considered to be ordered with the most significant byet
first, which means you have an unneeded leading zero, which is
discarded, just as you'd eliminiate the leading zeroes in the decimal
number 0010, resulting in 10.
crypto> the following program outputs:
crypto>
crypto> -----------------------
crypto> what the heck?
crypto> 0 41
crypto> 41 81
crypto> 81 c1
crypto> c1 1
crypto> 1 42
crypto> 42 82
crypto> 82 c2
crypto> c2 0
crypto> -----------------------
crypto>
crypto> is this the expected behavior?
crypto>
crypto>
crypto> #include <stdio.h>
crypto> #include <string.h>
crypto> #include <openssl/bn.h>
crypto>
crypto> static unsigned char data[8]={0x00,0x41,0x81,0xc1,0x01,0x42,0x82,0xc2};
crypto>
crypto> int main(int argc, char* argv[])
crypto> {
crypto> unsigned char aa[8];
crypto> BIGNUM *a;
crypto> int i;
crypto>
crypto> memset(aa, 0, 8);
crypto> a = BN_new();
crypto>
crypto> BN_bin2bn(data, 8, a);
crypto> BN_bn2bin(a, aa);
crypto>
crypto> if (memcmp(aa, data, 8) != 0)
crypto> printf("what the heck?\n");
crypto>
crypto> for (i = 0; i < 8; i++)
crypto> printf("%2x %2x\n", data[i], aa[i]);
crypto> }
--
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