Hi all,
Documentation says that, for EVP_EncryptUpdate, buffer of length (input length
+ cipher block size - 1) should be passed to output parameter.
Suppose if we take AES-128, if the input length is 33, output written by
EVP_EncryptUpdate will be 32. So, possible size could be
((input_length)/(cipher_block_size))*(cipher_block_size). What is the reason
for passing buffer of size (input length + cipher block size - 1)? Similarly
for EVP_DecryptUpdate, according to documentation, we have to pass (input
length + cipher block size).
As I can think of, all block ciphers have equal input block size and output
block size. Documentation says that amount of data written depends on the block
alignment of the encrypted data.
Can someone explain this to me?
I searched answers on the web and could not find anything useful.
Thanks in advance
DP
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