you may want to look at this thread https://www.mail-archive.com/[email protected]/msg03984.html
is not what you ask for, but is the closest thing i've seen also check if your pkgs have this patch applied https://review.openstack.org/#/c/59359/ On 03/05/2014 09:21 AM, sylecn wrote: > > I started two l3 agents on two nodes. In l3_agent.ini, I set one l3 agent's > handle_internal_only_routers to False, I config router_id to be ids of > the two > routers. And neutron agent-list show both l3 agents are up. if you want to an L3 agent to serve just a single router, why put 2 routers in router_id? > > Now when I boot instance with a port in subnet2, the traffic still go > through > the server that runs l3-agent1. do you have routers for subnet2 on both nodes? my bet is l3-agent1 created a router for subnet2, maybe it was started before l3-agent2 PD: i'm not very experienced with nat router and gre, i use vlan and external networks > > My question is: is this kind of network supported by neutron? Does the > router_id config means the l3 agent will manage that router only? The only > document mention its use is when use_namespace is False. In my case, I > have it > set to True. > > Side note: there is a question on > https://answers.launchpad.net/neutron/+question/236230 which says it's > possible to change router's l3 agent, but did not mention how. > > Any help is appreciated. > > / > YY Inc. is hiring openstack and python developers. Interested? Check > http://www.nsbeta.info/jobs/ > > -- > Thanks, > Yuanle > > > _______________________________________________ > Mailing list: http://lists.openstack.org/cgi-bin/mailman/listinfo/openstack > Post to : [email protected] > Unsubscribe : http://lists.openstack.org/cgi-bin/mailman/listinfo/openstack > -- 1AE0 322E B8F7 4717 BDEA BF1D 44BB 1BA7 9F6C 6333 _______________________________________________ Mailing list: http://lists.openstack.org/cgi-bin/mailman/listinfo/openstack Post to : [email protected] Unsubscribe : http://lists.openstack.org/cgi-bin/mailman/listinfo/openstack
