On 2006-11-23 00:22, Stevens wrote: > On Wednesday 22 November 2006 16:26, Darryl Gregorash wrote: > >> -- >> The best way to accelerate a computer running Windows is at 9.81 m/s² >> > > Is that the same as 32 ft/sec/sec as I was taught? Back in the dark > I have a vague memory of such a number (I am from Canada, which for the past 30 years has been an enlightened country ;-) ). Most likely they are the same thing.
> ages. It does help to have enough space to have the acceleration > flatten out to terminal velocity, then Windows is properly configured. > But that requires one have ready access to an aircraft or the top of a rather tall building, or be free to travel to the Grand Canyon. In practice, any close approximation to terminal velocity (ie. within 120 or 130 km/h) is sufficient. -- What *is* the terminal velocity of freely falling Microsoft Windows anyway? -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
