Am Sonntag, 28. Januar 2007 20:48 schrieb [EMAIL PROTECTED]: > I am still having problems with this for some reason(s). I actually > installed Mandriva this morning, got the bootloader to install and was able > to boot to it without having to use the DVD disc. I did have a little > trouble, but it was simple to fix because the problem was obvious. It was > pointing to a non-existant swap partition. I changed what people had > suggested yesterday in the menu.ist file and even edited the grub.conf > file, but no matter what I did, the error still came up and although I > changed the device from sda,7 to something else, it would put it back. > > The only reference to anything about hd0,0 is on the line for booting into > windows. it says: "rootnoverify (hd0,0)" and the entry below it says: > "chainloader (hd0,0)+1" > > I'm at a loss here. I thought I understood what M Harris was telling me > yesterday but I'm not sure anymore. :-( > > the drive itself is sda0 > > It has a primary partition (sda1), then a extended partition with two > logical partitions (NTFS) then the swap partition, the root partition and > the home partition. > > The extended partition is sda2 which I understand is always the case with > an extended partition. So the first (logical) partition would be sda5, the > second logical partition would be sda6, the swap partition is sda7, the > root partition is sda8 and the home partition is sda9. This is how Mandriva > saw it as well. Now counting the partitions is what I think is confusing > me. As far as the HD0,0) is concerned. Would it be like the following? sda1 > = hd0,1 or 0? How about the extended partition? would sda2 become hd0,1 or > 2? and so forth?
/dev/sda1 would become (hd0,0), /dev/sda2 would become (hd0,1) and so forth.
/dev/sdb3 would then become (hd1,2) for instance.
The last letter in sd{a,b,c,...} respectively is represented by hd{0,1,2,..}.
Analogical the partition number sda{1,2,3,...} corresponds to hd0,{0,1,2,..}.
> well, it's almost noon and I'm getting breakfast ready! :-O Hopefully
> someone can make sense of this. Many Thanks!
--
Alex
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