Hi Jonas,
Jonas Helgi Palsson <[EMAIL PROTECTED]> wrote:
> Hi
>
> On Tuesday 08 January 2008 14:00:38 Sebastian Reitenbach wrote:
> > Hi,
> >
> > I want to substitue some variable names, to build another variable,
> > therefore I have a script like this:
> >
> > #!/bin/bash
> > NETS="NET0 NET1 NET2"
> > NET0_IF=eth0
> > NET1_IF=eth1
> > NET2_IF=eth2
> >
> > CNT=0
> > for NET in $NETS;do
> > echo ${${NET}_IF}
> > done
> >
> > What I want is the output to look like like:
> > eth0
> > eth1
> > eth2
> >
> > but whatever I try, it ends with a "bad substitution", or wrong output.
> >
> > Is there a way of this kind of double substitution in bash?
> >
>
> Use "eval"
>
>
> #!/bin/bash
> NETS="NET0 NET1 NET2"
> NET0_IF=eth0
> NET1_IF=eth1
> NET2_IF=eth2
>
> CNT=0
> for NET in $NETS;do
> eval echo \$${NET}_IF
> done
thanks a lot for your fast answer, this is exactly what I was looking for.
sebastian
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