Ok, I don't know how to word my question properly.     I am writing a
script that greps for a string (for a command that has multiple lines of
output - the finger command)


My problem:   I want to take the standard output (1) from a grep
command, but I also want to add my own values to the resulting line.
Let's use a simple example:

My script:
-----------
for i in `sort /etc/passwd | cut -f1 -d":"`
do
  finger $i | grep -i last
done


The output will look like this:
--------------------------------
Last login Fri Jan 18 09:32 (SAST) on 57 from 163.197.212.133
Last login Fri Aug 31 13:06 (SAST) on 38 from 163.197.212.113
Last login Mon Jan 14 11:23 (SAST) on 39 from 163.197.208.90
Last login Wed Sep 12 08:00 (SAST) on 153 from 163.197.212.142
Last login Fri Jul  6 09:13 2007 (SAST) on 188 from 163.197.222.37
Last login Wed Feb 21 08:21 2007 (SAST) on 155 from 163.197.206.103
Last login Fri Jan 18 11:01 (SAST) on 218 from 163.197.212.11
Last login Thu Dec 20 10:50 (SAST) on 196 from 163.197.210.31
Last login Fri May  4 11:47 2007 (SAST) on 88 from 163.197.207.16
Last login Fri Jan 18 09:15 (SAST) on 81 from 163.197.212.83



BUT, I want to add the user's login to the lines above, for example:

$i: Last login Fri Jan 18 09:32 (SAST) on 57 from 163.197.212.133
$i: Last login Fri Aug 31 13:06 (SAST) on 38 from 163.197.212.113
$i: Last login Mon Jan 14 11:23 (SAST) on 39 from 163.197.208.90
$i: Last login Wed Sep 12 08:00 (SAST) on 153 from 163.197.212.142
$i: Last login Fri Jul  6 09:13 2007 (SAST) on 188 from 163.197.222.37

where $i is the login of the user from the script


How can I place $i, and the standard output of grep, on the same line
(make it 1 line of output) ?



Dirk


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