On Thu, Feb 09, 2012 at 05:12:26PM -0800, david wrote: > > i am a ruby developer, i live in china, sorry bother you. > i saw you works on github. i am interesting in ruote, i want to try it > in my project. One problem is that i do not know how to translate > existing xpdl files to right format. Ruota could understand it. > Could you give me some guides? I know there is tool ruota-transition, > but it seems long time no maintain.
Hello David, welcome to ruote's mailing-list. Since you were interested in ruote-transition, I've made the effort to renovate it: https://github.com/jmettraux/ruote-transition It should work, but its "compiler" is very naive. The best way to translate from XDPL to ruote, is to look at the graphical view of XPDL and rewrite as a ruote process definition. I recommend you study ruote process definitions and expressions http://ruote.rubyforge.org/expressions.html Try with simple things and then move on to more difficult things. If you need help as you move on, feel free to post questions here. Best regards, -- John Mettraux - http://lambda.io/processi -- you received this message because you are subscribed to the "ruote users" group. to post : send email to [email protected] to unsubscribe : send email to [email protected] more options : http://groups.google.com/group/openwferu-users?hl=en
