* Nathan Hintz <[email protected]> [19.10.2014 08:49]:
> > case "$leddc" in
> >     '0xffff'*)
> >             leddc='0x005a000a'
> >     ;;
> > esac
> > 
> > IMHO the approach from felix does not work:
> > root@box:~ echo $((0xffff))
> > 65535
> > root@box:~ echo $((0xffff\n))
> > -ash: arithmetic syntax error
> > 
> > the real would be the fix the output of 'wlc'.
> 
> 'wlc' is not broken, a simple test case demonstrates it works as expected:
> 
> root@e3000-1:~# wlc ifname wl0 leddc
> 0x005a000a
> root@e3000-1:~# wlc ifname wl0 leddc 0xffff
> root@e3000-1:~# wlc ifname wl0 leddc
> 0xffff
> root@e3000-1:~# leddc=$(wlc ifname wl0 leddc)
> root@e3000-1:~# [ "$leddc" = "0xffff" ] && echo yes
> yes
> root@e3000-1:~# wlc ifname wl0 leddc 0x005a000a
> root@e3000-1:~# wlc ifname wl0 leddc
> 0x005a000a
> root@e3000-1:~# leddc=$(wlc ifname wl0 leddc)
> root@e3000-1:~# [ "$leddc" = "0xffff" ] && echo yes
> root@e3000-1:~#

ah - ok. sorry felix - i really was thinking that it outputs
a string '0xffff\n' (with the symbol of a newline). so your
approach is correct but without quotes, so:

[ $((leddc)) -eq $((0xffff)) ] && ...

bye, bastian - please Álvaro send a new patch
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