> scott> VARIABLE rtc REFCURSOR
> scott> EXECUTE :rtc := rtc_dept
> begin :rtc := rtc_dept; end;
>
The first thing I notice is that the code
above is assinging an 'index by table' to a ref cursor.
You might start there.
Jared
On Mon, 19 Feb 2001, Eriovaldo do Carmo Andrietta wrote:
>
> Hi Friends :
>
> I have the code bellow and would like to return the variable type table.
>
>
> CREATE OR REPLACE PACKAGE cv_types AS
> TYPE DeptCurType is REF CURSOR RETURN dept%ROWTYPE;
> TYPE retorno IS TABLE OF SCOTT.dept%ROWTYPE INDEX BY BINARY_INTEGER;
> TYPE Tipo_Tabela_Emp IS TABLE OF EMP%ROWTYPE INDEX BY BINARY_INTEGER;
> TYPE Tipo_Tabela_Dept IS TABLE OF DEPT%ROWTYPE INDEX BY BINARY_INTEGER;
> END cv_types;
>
>
> create or replace function rtc_dept
> RETURN cv_types.Tipo_Tabela_Dept
> IS
> cursor resultset is
> select * from dept;
> tabdept cv_types.Tipo_tabela_Dept;
> I BINARY_INTEGER;
> tab dept%rowtype;
> BEGIN
> i := 1;
> open resultset;
> loop
> fetch resultset into tab;
> exit when resultset%notfound;
> tabdept(i).dname := '- ' || tab.dname;
> dbms_output.put_line (tabdept(i).dname);
> i := i + 1;
> end loop;
> close resultset;
> RETURN(tabdept);
> END;
>
> scott>
> scott>
> scott>
> scott> VARIABLE rtc REFCURSOR
> scott> EXECUTE :rtc := rtc_dept
> begin :rtc := rtc_dept; end;
>
> *
> ERROR at line 1:
> ORA-06550: line 1, column 15:
> PLS-00382: expression is of wrong type
> ORA-06550: line 1, column 7:
> PL/SQL: Statement ignored
>
>
> scott> PRINT rtc
> ERROR:
> ORA-24338: statement handle not executed
>
>
> Error printing variable "rtc"
> scott>
>
> what is wrong ?
>
> Eriovaldo do Carmo Andrietta
> Widesoft Sistemas Ltda.
> Limeira/SP - Brasil
>
>
>
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