If you are using korn shell, then why spawn a new process to do this.  Try:

a="somefile.gz"
if [ "$a" != "${a%.gz}" ] ; then
  echo "this is a gz file"
elif [ "$a" != "${a%.z}" ] ; then
  echo "this is a z file"
else
  echo "I don't know"
fi

You could also do this...

a="somefile.gz"
SUFFIX=".${a#*\.}"
FILE="${a%$SUFFIX}"
echo "$a  $FILE  $SUFFIX"

Ron.



                                                                                       
                           
                    cspence@FuelS                                                      
                           
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                    Sent by:             cc:                                           
                           
                    root@fatcity.        Subject:     RE: check file size, extension 
question???                  
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                    06/12/01                                                           
                           
                    05:38 PM                                                           
                           
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I will beat Jared to this, What about using Perl?

"Walking on water and developing software from a specification are easy if
both are frozen."

Christopher R. Spence
Oracle DBA
Fuelspot



-----Original Message-----
Sent: Tuesday, June 12, 2001 7:58 PM
To: Multiple recipients of list ORACLE-L


Hi, all

I'm writing some auto backup/refresh script, do you
know any command that returns only size or extenstion
or a file? (there will be only one file in the
directory)

I know awk can return only a part of the output, but
somehow I cann't combine awk and ls -l successfully.
ls -s returns some size I don't want, I'd like to have
size as shown in ls -l.

For the refresh script, I like to check file
extension, so if it's in gz, I'll gunzip; if it's Z,
I'll uncompress.

Thanks!

Andrea

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