DOH! Answered my own question... select max(MYCOUNT)-min(MYCOUNT) from MYTABLE group by round(rownum/2+.5)*2 UNION select max(MYCOUNT)-min(MYCOUNT) from MYTABLE group by round((rownum-1)/2+.5)*2 If I had just experimented 1 more minute before writing that message.... <blush> Rich Jesse System/Database Administrator [EMAIL PROTECTED] Quad/Tech International, Sussex, WI USA -----Original Message----- Sent: Monday, June 18, 2001 14:34 To: '[EMAIL PROTECTED]' Hi all, I've got a table, MYTABLE: MYCOUNT number MYDATE date, UNIQUE e.g: MYCOUNT MYDATE 12509 06/17/2001 12:01 12934 06/17/2001 12:06 13452 06/17/2001 12:11 13455 06/17/2001 12:16 I need to get the difference between MYCOUNT on two consecutive rows (consecutive MYDATEs). MYCOUNT cannot be less than the MYCOUNT chronologically before it. Is there a simple SELECT that I can use for this WITHOUT a cursor? I've come close: select max(MYCOUNT)-min(MYCOUNT) from MYTABLE group by round(rownum/2+.5)*2 But this only gives me diffs from rows 1, 2-3, 4-5, 6-7, etc., while I need the diffs from rows 1-2, 2-3, 3-4, 4-5... AAAALLLMOST! TIA, Rich Jesse System/Database Administrator [EMAIL PROTECTED] Quad/Tech International, Sussex, WI USA -- Please see the official ORACLE-L FAQ: http://www.orafaq.com -- Author: Jesse, Rich INET: [EMAIL PROTECTED] Fat City Network Services -- (858) 538-5051 FAX: (858) 538-5051 San Diego, California -- Public Internet access / Mailing Lists -------------------------------------------------------------------- To REMOVE yourself from this mailing list, send an E-Mail message to: [EMAIL PROTECTED] (note EXACT spelling of 'ListGuru') and in the message BODY, include a line containing: UNSUB ORACLE-L (or the name of mailing list you want to be removed from). You may also send the HELP command for other information (like subscribing).